Which point on Figure E5-1 best represents the impedance of a series circuit consisting of a 400-ohm resistor and a 38-picofarad capacitor at 14 MHz?
Why For a series RC circuit the impedance is Z = R - jXc, so you need the capacitive reactance. Xc = 1/(2*pi*f*C) = 1/(6.2832 x 14,000,000 x 38 x 10^-12), which works out to about 300 ohms. That gives Z = 400 - j300, plotted at 400 on the resistance (horizontal) axis and 300 units below the axis because capacitive reactance is negative. That location on the chart is point 4.
Watch out The tempting trap is the mirror-image point at 400 + j300, which is what you would get from a 400-ohm resistor in series with an inductor; capacitors always plot below the real axis.
Capacitors hang down: minus j, below the axis. Inductors point up. Get R first, then Xc = 1/(2*pi*f*C).