Which point in Figure E5-1 best represents the impedance of a series circuit consisting of a 300-ohm resistor and an 18-microhenry inductor at 3.505 MHz?
Why Compute the inductive reactance first: XL = 2*pi*f*L = 2*pi*(3.505e6)(18e-6), which comes to about 396 ohms, essentially 400 ohms. In series the resistance and reactance add as a complex number, so Z = 300 + j396, roughly 300 + j400 ohms. On the graph that is a point 300 units to the right on the resistance axis and about 400 units up on the positive (inductive) reactance axis, which is Point 3.
Watch out The mirror-image point below the axis represents 300 - j400, a capacitive reactance, and points with the 400 and 300 swapped correspond to a different resistor and reactance pair, so check which axis carries which number.
XL = 2*pi*f*L; inductive means plot ABOVE the axis, capacitive below.