What is the resonant frequency of an RLC circuit if R is 22 ohms, L is 50 microhenries, and C is 40 picofarads?
Why Resonance depends only on L and C: f = 1 / (2π√(LC)). Here LC = (50 × 10^-6)(40 × 10^-12) = 2 × 10^-15, whose square root is 4.472 × 10^-8. Multiplying by 2π gives 2.81 × 10^-7, and the reciprocal is about 3.56 MHz. The 22 ohms of resistance affects Q and bandwidth but has no effect on the resonant frequency.
Watch out The 22.36 MHz choice is what you get by computing 1/√(LC) and calling it hertz, which forgets the 2π factor; that number is actually the resonant frequency in radians per second.
Resonance ignores R. f = 1/(2π√LC), and never drop the 2π or you land on the tempting 22.36 MHz.