Why In a series resonant circuit the current through L and C is maximized at resonance, and the reactive voltages across the inductor and capacitor are each Q times the applied voltage. These two voltages are equal and opposite so they cancel as seen by the source, but they are physically present across the components. So raising Q directly raises those internal voltages, which is why high-Q series circuits need components rated well above the supply voltage.
Watch out Minimizing parasitics is a way to get high Q, not a result of it; stray resistance and loss are what lower Q in the first place.
Series resonance: V across L and C = Q x source voltage. High Q means high internal volts.
With a Q of 100, a 10 volt source puts 1000 volts across the series capacitor. More Q, more volts inside the box.